PROBLEM STATEMENT
In Chemistry, there's a different meaning to the word 'solution' than in programming. When we mix 
x liters of some substance with (100-x) liters of water, we get 100 liters of x-% solution of that 
substance.
You are given several bottles containing solutions of the same substance. The i-th bottle contains 
amount[i] liters of percent[i]-% solution. Return the maximal number of liters of need-% solution 
we can get by pouring together some of these bottles (possibly partially, see example 0).

DEFINITION
Class:MixingLiquids
Method:howMuch
Parameters:vector <int>, vector <int>, int
Returns:double
Method signature:double howMuch(vector <int> percent, vector <int> amount, int need)


NOTES
-The returned value must have an absolute or relative error less than 1e-9.


CONSTRAINTS
-percent will contain between 1 and 50 elements, inclusive.
-Each element of percent will be between 0 and 100, inclusive.
-amount will contain the same number of elements as percent.
-Each element of amount will be between 1 and 1000, inclusive.
-need will be between 0 and 100, inclusive.


EXAMPLES

0)
{0, 100}
{20, 30}
50

Returns: 40.0

We have 20 liters of water and 30 liters of pure substance. We need a 50% solution, so we combine 
all the water with 20 liters of substance.

1)
{0, 100}
{20, 30}
60

Returns: 50.0

We can use everything we have.

2)
{90, 70, 80}
{10, 10, 10}
50

Returns: 0.0

All our bottles contain too much substance.

3)
{30, 80, 60}
{40, 10, 15}
57

Returns: 35.18518518518519



4)
{50,50,50}
{395,971,964}
50

Returns: 2330.0

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