PROBLEM STATEMENT
There is nothing more beautiful than just an integer number.
You are given an integer n. Write down n in decimal notation with no leading zeroes, and let M be
the number of written digits. Perform the following operation exactly k times:
Choose two different 1-based positions, i and j, such that 1 <= i < j <= M. Swap the digits
at positions i and j. This swap must not cause the resulting number to have a leading zero, i.e.,
if the digit at position j is zero, then i must be strictly greater than 1.
Return the maximal possible number you can get at the end of this procedure. If it's not possible
to perform k operations, return -1 instead.
DEFINITION
Class:TheSwap
Method:findMax
Parameters:int, int
Returns:int
Method signature:int findMax(int n, int k)
CONSTRAINTS
-n will be between 1 and 1,000,000, inclusive.
-k will be between 1 and 10, inclusive.
EXAMPLES
0)
16375
1
Returns: 76315
The optimal way is to swap 1 and 7.
1)
432
1
Returns: 423
In this case the result is less than the given number.
2)
90
4
Returns: -1
We can't make even a single operation because it would cause the resulting number to have a
leading zero.
3)
5
2
Returns: -1
Here we can't choose two different positions for an operation.
4)
436659
2
Returns: 966354
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